3(K+2)+2(k+3)=2k+15

Solution for 3(K+2)+2(k+3)=2k+15 equation:

Simplifying
3(K + 2) + 2(k + 3) = 2k + 15

Reorder the terms:
3(2 + K) + 2(k + 3) = 2k + 15
(2 * 3 + K * 3) + 2(k + 3) = 2k + 15
(6 + 3K) + 2(k + 3) = 2k + 15

Reorder the terms:
6 + 3K + 2(3 + k) = 2k + 15
6 + 3K + (3 * 2 + k * 2) = 2k + 15
6 + 3K + (6 + 2k) = 2k + 15

Reorder the terms:
6 + 6 + 3K + 2k = 2k + 15

Combine like terms: 6 + 6 = 12
12 + 3K + 2k = 2k + 15

Reorder the terms:
12 + 3K + 2k = 15 + 2k

Add '-2k' to each side of the equation.
12 + 3K + 2k + -2k = 15 + 2k + -2k

Combine like terms: 2k + -2k = 0
12 + 3K + 0 = 15 + 2k + -2k
12 + 3K = 15 + 2k + -2k

Combine like terms: 2k + -2k = 0
12 + 3K = 15 + 0
12 + 3K = 15

Solving
12 + 3K = 15

Solving for variable 'K'.

Move all terms containing K to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 3K = 15 + -12

Combine like terms: 12 + -12 = 0
0 + 3K = 15 + -12
3K = 15 + -12

Combine like terms: 15 + -12 = 3
3K = 3

Divide each side by '3'.
K = 1

Simplifying
K = 1