3(N+1)=4(N-5)

Solution for 3(N+1)=4(N-5) equation:

Simplifying
3(N + 1) = 4(N + -5)

Reorder the terms:
3(1 + N) = 4(N + -5)
(1 * 3 + N * 3) = 4(N + -5)
(3 + 3N) = 4(N + -5)

Reorder the terms:
3 + 3N = 4(-5 + N)
3 + 3N = (-5 * 4 + N * 4)
3 + 3N = (-20 + 4N)

Solving
3 + 3N = -20 + 4N

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '-4N' to each side of the equation.
3 + 3N + -4N = -20 + 4N + -4N

Combine like terms: 3N + -4N = -1N
3 + -1N = -20 + 4N + -4N

Combine like terms: 4N + -4N = 0
3 + -1N = -20 + 0
3 + -1N = -20

Add '-3' to each side of the equation.
3 + -3 + -1N = -20 + -3

Combine like terms: 3 + -3 = 0
0 + -1N = -20 + -3
-1N = -20 + -3

Combine like terms: -20 + -3 = -23
-1N = -23

Divide each side by '-1'.
N = 23

Simplifying
N = 23