3(X+1)+2(2x+-3)=5(X-1)+8

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Solution for 3(X+1)+2(2x+-3)=5(X-1)+8 equation: 



3(X+1)+2(2X+-3)=5(X-1)+8

We move all terms to the left:

3(X+1)+2(2X+-3)-(5(X-1)+8)=0

We add all the numbers together, and all the variables

3(X+1)+2(2X-3)-(5(X-1)+8)=0

We multiply parentheses

3X+4X-(5(X-1)+8)+3-6=0



We calculate terms in parentheses: -(5(X-1)+8), so:

5(X-1)+8

We multiply parentheses

5X-5+8

We add all the numbers together, and all the variables

5X+3

Back to the equation:

-(5X+3)



We add all the numbers together, and all the variables

7X-(5X+3)-3=0

We get rid of parentheses

7X-5X-3-3=0

We add all the numbers together, and all the variables

2X-6=0

We move all terms containing X to the left, all other terms to the right

2X=6

X=6/2

X=3

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