3(X+1)+4(X-2)=16

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Solution for 3(X+1)+4(X-2)=16 equation: 


Simplifying
3(X + 1) + 4(X + -2) = 16

Reorder the terms:
3(1 + X) + 4(X + -2) = 16
(1 * 3 + X * 3) + 4(X + -2) = 16
(3 + 3X) + 4(X + -2) = 16

Reorder the terms:
3 + 3X + 4(-2 + X) = 16
3 + 3X + (-2 * 4 + X * 4) = 16
3 + 3X + (-8 + 4X) = 16

Reorder the terms:
3 + -8 + 3X + 4X = 16

Combine like terms: 3 + -8 = -5
-5 + 3X + 4X = 16

Combine like terms: 3X + 4X = 7X
-5 + 7X = 16

Solving
-5 + 7X = 16

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 7X = 16 + 5

Combine like terms: -5 + 5 = 0
0 + 7X = 16 + 5
7X = 16 + 5

Combine like terms: 16 + 5 = 21
7X = 21

Divide each side by '7'.
X = 3

Simplifying
X = 3

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