3(X+10)+2(X-5)=40

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Solution for 3(X+10)+2(X-5)=40 equation:


Simplifying
3(X + 10) + 2(X + -5) = 40

Reorder the terms:
3(10 + X) + 2(X + -5) = 40
(10 * 3 + X * 3) + 2(X + -5) = 40
(30 + 3X) + 2(X + -5) = 40

Reorder the terms:
30 + 3X + 2(-5 + X) = 40
30 + 3X + (-5 * 2 + X * 2) = 40
30 + 3X + (-10 + 2X) = 40

Reorder the terms:
30 + -10 + 3X + 2X = 40

Combine like terms: 30 + -10 = 20
20 + 3X + 2X = 40

Combine like terms: 3X + 2X = 5X
20 + 5X = 40

Solving
20 + 5X = 40

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 5X = 40 + -20

Combine like terms: 20 + -20 = 0
0 + 5X = 40 + -20
5X = 40 + -20

Combine like terms: 40 + -20 = 20
5X = 20

Divide each side by '5'.
X = 4

Simplifying
X = 4

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