3(X+2)-2(X+1)=8

Solution for 3(X+2)-2(X+1)=8 equation:

Simplifying
3(X + 2) + -2(X + 1) = 8

Reorder the terms:
3(2 + X) + -2(X + 1) = 8
(2 * 3 + X * 3) + -2(X + 1) = 8
(6 + 3X) + -2(X + 1) = 8

Reorder the terms:
6 + 3X + -2(1 + X) = 8
6 + 3X + (1 * -2 + X * -2) = 8
6 + 3X + (-2 + -2X) = 8

Reorder the terms:
6 + -2 + 3X + -2X = 8

Combine like terms: 6 + -2 = 4
4 + 3X + -2X = 8

Combine like terms: 3X + -2X = 1X
4 + 1X = 8

Solving
4 + 1X = 8

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1X = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 1X = 8 + -4
1X = 8 + -4

Combine like terms: 8 + -4 = 4
1X = 4

Divide each side by '1'.
X = 4

Simplifying
X = 4