3(X+40)-4=2(X+4)+X

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Solution for 3(X+40)-4=2(X+4)+X equation: 


Simplifying
3(X + 40) + -4 = 2(X + 4) + X

Reorder the terms:
3(40 + X) + -4 = 2(X + 4) + X
(40 * 3 + X * 3) + -4 = 2(X + 4) + X
(120 + 3X) + -4 = 2(X + 4) + X

Reorder the terms:
120 + -4 + 3X = 2(X + 4) + X

Combine like terms: 120 + -4 = 116
116 + 3X = 2(X + 4) + X

Reorder the terms:
116 + 3X = 2(4 + X) + X
116 + 3X = (4 * 2 + X * 2) + X
116 + 3X = (8 + 2X) + X

Combine like terms: 2X + X = 3X
116 + 3X = 8 + 3X

Add '-3X' to each side of the equation.
116 + 3X + -3X = 8 + 3X + -3X

Combine like terms: 3X + -3X = 0
116 + 0 = 8 + 3X + -3X
116 = 8 + 3X + -3X

Combine like terms: 3X + -3X = 0
116 = 8 + 0
116 = 8

Solving
116 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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