3(X-7)+5(x-4)=15R

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Solution for 3(X-7)+5(x-4)=15R equation: 



3(X-7)+5(X-4)=15

We move all terms to the left:

3(X-7)+5(X-4)-(15)=0

We multiply parentheses

3X+5X-21-20-15=0

We add all the numbers together, and all the variables

8X-56=0

We move all terms containing X to the left, all other terms to the right

8X=56

X=56/8

X=7

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