3(Y-1)+4(2+b)=4b(y+1)

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Solution for 3(Y-1)+4(2+b)=4b(y+1) equation:


Simplifying
3(Y + -1) + 4(2 + b) = 4b(y + 1)

Reorder the terms:
3(-1 + Y) + 4(2 + b) = 4b(y + 1)
(-1 * 3 + Y * 3) + 4(2 + b) = 4b(y + 1)
(-3 + 3Y) + 4(2 + b) = 4b(y + 1)
-3 + 3Y + (2 * 4 + b * 4) = 4b(y + 1)
-3 + 3Y + (8 + 4b) = 4b(y + 1)

Reorder the terms:
-3 + 8 + 3Y + 4b = 4b(y + 1)

Combine like terms: -3 + 8 = 5
5 + 3Y + 4b = 4b(y + 1)

Reorder the terms:
5 + 3Y + 4b = 4b(1 + y)
5 + 3Y + 4b = (1 * 4b + y * 4b)
5 + 3Y + 4b = (4b + 4by)

Add '-4b' to each side of the equation.
5 + 3Y + 4b + -4b = 4b + -4b + 4by

Combine like terms: 4b + -4b = 0
5 + 3Y + 0 = 4b + -4b + 4by
5 + 3Y = 4b + -4b + 4by

Combine like terms: 4b + -4b = 0
5 + 3Y = 0 + 4by
5 + 3Y = 4by

Solving
5 + 3Y = 4by

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 3Y = -5 + 4by

Combine like terms: 5 + -5 = 0
0 + 3Y = -5 + 4by
3Y = -5 + 4by

Divide each side by '3'.
Y = -1.666666667 + 1.333333333by

Simplifying
Y = -1.666666667 + 1.333333333by

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