3(Y-4)+Y=2(6+2Y)

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Solution for 3(Y-4)+Y=2(6+2Y) equation: 


Simplifying
3(Y + -4) + Y = 2(6 + 2Y)

Reorder the terms:
3(-4 + Y) + Y = 2(6 + 2Y)
(-4 * 3 + Y * 3) + Y = 2(6 + 2Y)
(-12 + 3Y) + Y = 2(6 + 2Y)

Combine like terms: 3Y + Y = 4Y
-12 + 4Y = 2(6 + 2Y)
-12 + 4Y = (6 * 2 + 2Y * 2)
-12 + 4Y = (12 + 4Y)

Add '-4Y' to each side of the equation.
-12 + 4Y + -4Y = 12 + 4Y + -4Y

Combine like terms: 4Y + -4Y = 0
-12 + 0 = 12 + 4Y + -4Y
-12 = 12 + 4Y + -4Y

Combine like terms: 4Y + -4Y = 0
-12 = 12 + 0
-12 = 12

Solving
-12 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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