3(a+1)+2a=-(3a-5)+8

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Solution for 3(a+1)+2a=-(3a-5)+8 equation: 



3(a+1)+2a=-(3a-5)+8

We move all terms to the left:

3(a+1)+2a-(-(3a-5)+8)=0

We add all the numbers together, and all the variables

2a+3(a+1)-(-(3a-5)+8)=0

We multiply parentheses

2a+3a-(-(3a-5)+8)+3=0



We calculate terms in parentheses: -(-(3a-5)+8), so:

-(3a-5)+8

We get rid of parentheses

-3a+5+8

We add all the numbers together, and all the variables

-3a+13

Back to the equation:

-(-3a+13)



We add all the numbers together, and all the variables

5a-(-3a+13)+3=0

We get rid of parentheses

5a+3a-13+3=0

We add all the numbers together, and all the variables

8a-10=0

We move all terms containing a to the left, all other terms to the right

8a=10

a=10/8

a=1+1/4

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