3(a+1)-5=(3a-2)

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Solution for 3(a+1)-5=(3a-2) equation:


Simplifying
3(a + 1) + -5 = (3a + -2)

Reorder the terms:
3(1 + a) + -5 = (3a + -2)
(1 * 3 + a * 3) + -5 = (3a + -2)
(3 + 3a) + -5 = (3a + -2)

Reorder the terms:
3 + -5 + 3a = (3a + -2)

Combine like terms: 3 + -5 = -2
-2 + 3a = (3a + -2)

Reorder the terms:
-2 + 3a = (-2 + 3a)

Remove parenthesis around (-2 + 3a)
-2 + 3a = -2 + 3a

Add '2' to each side of the equation.
-2 + 2 + 3a = -2 + 2 + 3a

Combine like terms: -2 + 2 = 0
0 + 3a = -2 + 2 + 3a
3a = -2 + 2 + 3a

Combine like terms: -2 + 2 = 0
3a = 0 + 3a
3a = 3a

Add '-3a' to each side of the equation.
3a + -3a = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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