3(a+1)4a=24

Solution for 3(a+1)4a=24 equation:

3(a+1)4a=24

We move all terms to the left:

3(a+1)4a-(24)=0

We multiply parentheses

12a^2+12a-24=0

a = 12; b = 12; c = -24;
Δ = b2-4ac
Δ = 122-4·12·(-24)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*12}=\frac{-48}{24}
=-2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*12}=\frac{24}{24}
=1
$