3(a+1)=19-5

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Solution for 3(a+1)=19-5 equation:



3(a+1)=19-5
We move all terms to the left:
3(a+1)-(19-5)=0
We add all the numbers together, and all the variables
3(a+1)-14=0
We multiply parentheses
3a+3-14=0
We add all the numbers together, and all the variables
3a-11=0
We move all terms containing a to the left, all other terms to the right
3a=11
a=11/3
a=3+2/3

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