3(a+2)+2(a-4)=3a+10

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Solution for 3(a+2)+2(a-4)=3a+10 equation: 



3(a+2)+2(a-4)=3a+10

We move all terms to the left:

3(a+2)+2(a-4)-(3a+10)=0

We multiply parentheses

3a+2a-(3a+10)+6-8=0

We get rid of parentheses

3a+2a-3a-10+6-8=0

We add all the numbers together, and all the variables

2a-12=0

We move all terms containing a to the left, all other terms to the right

2a=12

a=12/2

a=6

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