3(a+2)+2(a-5)=10

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Solution for 3(a+2)+2(a-5)=10 equation:



3(a+2)+2(a-5)=10
We move all terms to the left:
3(a+2)+2(a-5)-(10)=0
We multiply parentheses
3a+2a+6-10-10=0
We add all the numbers together, and all the variables
5a-14=0
We move all terms containing a to the left, all other terms to the right
5a=14
a=14/5
a=2+4/5

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