3(a+2)-2a=1/7(7a+42)

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Solution for 3(a+2)-2a=1/7(7a+42) equation: 



3(a+2)-2a=1/7(7a+42)

We move all terms to the left:

3(a+2)-2a-(1/7(7a+42))=0



Domain of the equation: 7(7a+42))!=0

a∈R



We add all the numbers together, and all the variables

-2a+3(a+2)-(1/7(7a+42))=0

We multiply parentheses

-2a+3a-(1/7(7a+42))+6=0

We multiply all the terms by the denominator


-2a*7(7a+42))+3a*7(7a+42))-(1+6*7(7a+42))=0

We add all the numbers together, and all the variables

-2a*7(7a+42))+3a*7(7a+42))-(1+6*7(7a=0

Wy multiply elements

-98a^3(7+42))-(1+6*7(7a=0

We do not support eapression: a^3(7

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