3(a+2)=11-2(a-5)

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Solution for 3(a+2)=11-2(a-5) equation: 



3(a+2)=11-2(a-5)

We move all terms to the left:

3(a+2)-(11-2(a-5))=0

We multiply parentheses

3a-(11-2(a-5))+6=0



We calculate terms in parentheses: -(11-2(a-5)), so:

11-2(a-5)

determiningTheFunctionDomain
-2(a-5)+11

We multiply parentheses

-2a+10+11

We add all the numbers together, and all the variables

-2a+21

Back to the equation:

-(-2a+21)



We get rid of parentheses

3a+2a-21+6=0

We add all the numbers together, and all the variables

5a-15=0

We move all terms containing a to the left, all other terms to the right

5a=15

a=15/5

a=3

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