3(a+2)=2(a+3)-5

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Solution for 3(a+2)=2(a+3)-5 equation:



3(a+2)=2(a+3)-5
We move all terms to the left:
3(a+2)-(2(a+3)-5)=0
We multiply parentheses
3a-(2(a+3)-5)+6=0
We calculate terms in parentheses: -(2(a+3)-5), so:
2(a+3)-5
We multiply parentheses
2a+6-5
We add all the numbers together, and all the variables
2a+1
Back to the equation:
-(2a+1)
We get rid of parentheses
3a-2a-1+6=0
We add all the numbers together, and all the variables
a+5=0
We move all terms containing a to the left, all other terms to the right
a=-5

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