3(a+2)=2(a-5)

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Solution for 3(a+2)=2(a-5) equation: 



3(a+2)=2(a-5)

We move all terms to the left:

3(a+2)-(2(a-5))=0

We multiply parentheses

3a-(2(a-5))+6=0



We calculate terms in parentheses: -(2(a-5)), so:

2(a-5)

We multiply parentheses

2a-10

Back to the equation:

-(2a-10)



We get rid of parentheses

3a-2a+10+6=0

We add all the numbers together, and all the variables

a+16=0

We move all terms containing a to the left, all other terms to the right

a=-16

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