3(a+20)=4(12-2a)

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Solution for 3(a+20)=4(12-2a) equation: 



3(a+20)=4(12-2a)

We move all terms to the left:

3(a+20)-(4(12-2a))=0

We add all the numbers together, and all the variables

3(a+20)-(4(-2a+12))=0

We multiply parentheses

3a-(4(-2a+12))+60=0



We calculate terms in parentheses: -(4(-2a+12)), so:

4(-2a+12)

We multiply parentheses

-8a+48

Back to the equation:

-(-8a+48)



We get rid of parentheses

3a+8a-48+60=0

We add all the numbers together, and all the variables

11a+12=0

We move all terms containing a to the left, all other terms to the right

11a=-12

a=-12/11

a=-1+1/11

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