3(a+4)+6a=3(a+4)+30

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Solution for 3(a+4)+6a=3(a+4)+30 equation: 



3(a+4)+6a=3(a+4)+30

We move all terms to the left:

3(a+4)+6a-(3(a+4)+30)=0

We add all the numbers together, and all the variables

6a+3(a+4)-(3(a+4)+30)=0

We multiply parentheses

6a+3a-(3(a+4)+30)+12=0



We calculate terms in parentheses: -(3(a+4)+30), so:

3(a+4)+30

We multiply parentheses

3a+12+30

We add all the numbers together, and all the variables

3a+42

Back to the equation:

-(3a+42)



We add all the numbers together, and all the variables

9a-(3a+42)+12=0

We get rid of parentheses

9a-3a-42+12=0

We add all the numbers together, and all the variables

6a-30=0

We move all terms containing a to the left, all other terms to the right

6a=30

a=30/6

a=5

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