3(a+4b-2c)=

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Solution for 3(a+4b-2c)= equation:


Simplifying
3(a + 4b + -2c) = 0
(a * 3 + 4b * 3 + -2c * 3) = 0
(3a + 12b + -6c) = 0

Solving
3a + 12b + -6c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12b' to each side of the equation.
3a + 12b + -12b + -6c = 0 + -12b

Combine like terms: 12b + -12b = 0
3a + 0 + -6c = 0 + -12b
3a + -6c = 0 + -12b
Remove the zero:
3a + -6c = -12b

Add '6c' to each side of the equation.
3a + -6c + 6c = -12b + 6c

Combine like terms: -6c + 6c = 0
3a + 0 = -12b + 6c
3a = -12b + 6c

Divide each side by '3'.
a = -4b + 2c

Simplifying
a = -4b + 2c

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