3(a+a)=19-5

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Solution for 3(a+a)=19-5 equation: 



3(a+a)=19-5

We move all terms to the left:

3(a+a)-(19-5)=0

We add all the numbers together, and all the variables

3(+2a)-14=0

We multiply parentheses

6a-14=0

We move all terms containing a to the left, all other terms to the right

6a=14

a=14/6

a=2+1/3

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