3(a+a)=4(4+2a)

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Solution for 3(a+a)=4(4+2a) equation: 



3(a+a)=4(4+2a)

We move all terms to the left:

3(a+a)-(4(4+2a))=0

We add all the numbers together, and all the variables

3(+2a)-(4(2a+4))=0

We multiply parentheses

6a-(4(2a+4))=0



We calculate terms in parentheses: -(4(2a+4)), so:

4(2a+4)

We multiply parentheses

8a+16

Back to the equation:

-(8a+16)



We get rid of parentheses

6a-8a-16=0

We add all the numbers together, and all the variables

-2a-16=0

We move all terms containing a to the left, all other terms to the right

-2a=16

a=16/-2

a=-8

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