3(a+b)=3a+3b

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Solution for 3(a+b)=3a+3b equation: 


Simplifying
3(a + b) = 3a + 3b
(a * 3 + b * 3) = 3a + 3b
(3a + 3b) = 3a + 3b

Add '-3a' to each side of the equation.
3a + -3a + 3b = 3a + -3a + 3b

Combine like terms: 3a + -3a = 0
0 + 3b = 3a + -3a + 3b
3b = 3a + -3a + 3b

Combine like terms: 3a + -3a = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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