3(a+m)+2(b+n)-3a-2b=0

Solution for 3(a+m)+2(b+n)-3a-2b=0 equation:

Simplifying
3(a + m) + 2(b + n) + -3a + -2b = 0
(a * 3 + m * 3) + 2(b + n) + -3a + -2b = 0
(3a + 3m) + 2(b + n) + -3a + -2b = 0
3a + 3m + (b * 2 + n * 2) + -3a + -2b = 0
3a + 3m + (2b + 2n) + -3a + -2b = 0

Reorder the terms:
3a + -3a + 2b + -2b + 3m + 2n = 0

Combine like terms: 3a + -3a = 0
0 + 2b + -2b + 3m + 2n = 0
2b + -2b + 3m + 2n = 0

Combine like terms: 2b + -2b = 0
0 + 3m + 2n = 0
3m + 2n = 0

Solving
3m + 2n = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2n' to each side of the equation.
3m + 2n + -2n = 0 + -2n

Combine like terms: 2n + -2n = 0
3m + 0 = 0 + -2n
3m = 0 + -2n
Remove the zero:
3m = -2n

Divide each side by '3'.
m = -0.6666666667n

Simplifying
m = -0.6666666667n