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3(a-2)=2(a+2)
We move all terms to the left:
3(a-2)-(2(a+2))=0
We multiply parentheses
3a-(2(a+2))-6=0
We calculate terms in parentheses: -(2(a+2)), so:We get rid of parentheses
2(a+2)
We multiply parentheses
2a+4
Back to the equation:
-(2a+4)
3a-2a-4-6=0
We add all the numbers together, and all the variables
a-10=0
We move all terms containing a to the left, all other terms to the right
a=10
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