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3(a-2)=6a(3a-6)
We move all terms to the left:
3(a-2)-(6a(3a-6))=0
We multiply parentheses
3a-(6a(3a-6))-6=0
We calculate terms in parentheses: -(6a(3a-6)), so:We get rid of parentheses
6a(3a-6)
We multiply parentheses
18a^2-36a
Back to the equation:
-(18a^2-36a)
-18a^2+3a+36a-6=0
We add all the numbers together, and all the variables
-18a^2+39a-6=0
a = -18; b = 39; c = -6;
Δ = b2-4ac
Δ = 392-4·(-18)·(-6)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-33}{2*-18}=\frac{-72}{-36} =+2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+33}{2*-18}=\frac{-6}{-36} =1/6 $
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