3(a-2)=a+1-7(-2a-1)

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Solution for 3(a-2)=a+1-7(-2a-1) equation: 



3(a-2)=a+1-7(-2a-1)

We move all terms to the left:

3(a-2)-(a+1-7(-2a-1))=0

We multiply parentheses

3a-(a+1-7(-2a-1))-6=0



We calculate terms in parentheses: -(a+1-7(-2a-1)), so:

a+1-7(-2a-1)

determiningTheFunctionDomain
a-7(-2a-1)+1

We multiply parentheses

a+14a+7+1

We add all the numbers together, and all the variables

15a+8

Back to the equation:

-(15a+8)



We get rid of parentheses

3a-15a-8-6=0

We add all the numbers together, and all the variables

-12a-14=0

We move all terms containing a to the left, all other terms to the right

-12a=14

a=14/-12

a=-1+1/6

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