3(a-4)+6a-7=(a-3)-(3a+5)

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Solution for 3(a-4)+6a-7=(a-3)-(3a+5) equation: 



3(a-4)+6a-7=(a-3)-(3a+5)

We move all terms to the left:

3(a-4)+6a-7-((a-3)-(3a+5))=0

We add all the numbers together, and all the variables

6a+3(a-4)-((a-3)-(3a+5))-7=0

We multiply parentheses

6a+3a-((a-3)-(3a+5))-12-7=0



We calculate terms in parentheses: -((a-3)-(3a+5)), so:

(a-3)-(3a+5)

We get rid of parentheses

a-3a-3-5

We add all the numbers together, and all the variables

-2a-8

Back to the equation:

-(-2a-8)



We add all the numbers together, and all the variables

9a-(-2a-8)-19=0

We get rid of parentheses

9a+2a+8-19=0

We add all the numbers together, and all the variables

11a-11=0

We move all terms containing a to the left, all other terms to the right

11a=11

a=11/11

a=1

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