3(a-4)-5a=-6+5(a-4)

Solution for 3(a-4)-5a=-6+5(a-4) equation:

3(a-4)-5a=-6+5(a-4)

We move all terms to the left:

3(a-4)-5a-(-6+5(a-4))=0

We add all the numbers together, and all the variables

-5a+3(a-4)-(-6+5(a-4))=0

We multiply parentheses

-5a+3a-(-6+5(a-4))-12=0


We calculate terms in parentheses: -(-6+5(a-4)), so:

-6+5(a-4)

determiningTheFunctionDomain
5(a-4)-6

We multiply parentheses

5a-20-6

We add all the numbers together, and all the variables

5a-26

Back to the equation:

-(5a-26)


We add all the numbers together, and all the variables

-2a-(5a-26)-12=0

We get rid of parentheses

-2a-5a+26-12=0

We add all the numbers together, and all the variables

-7a+14=0

We move all terms containing a to the left, all other terms to the right

-7a=-14

a=-14/-7

a=+2