3(a-4)=2(-2a+1)

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Solution for 3(a-4)=2(-2a+1) equation: 



3(a-4)=2(-2a+1)

We move all terms to the left:

3(a-4)-(2(-2a+1))=0

We multiply parentheses

3a-(2(-2a+1))-12=0



We calculate terms in parentheses: -(2(-2a+1)), so:

2(-2a+1)

We multiply parentheses

-4a+2

Back to the equation:

-(-4a+2)



We get rid of parentheses

3a+4a-2-12=0

We add all the numbers together, and all the variables

7a-14=0

We move all terms containing a to the left, all other terms to the right

7a=14

a=14/7

a=2

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