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3(a-4)=2(5+a)
We move all terms to the left:
3(a-4)-(2(5+a))=0
We add all the numbers together, and all the variables
3(a-4)-(2(a+5))=0
We multiply parentheses
3a-(2(a+5))-12=0
We calculate terms in parentheses: -(2(a+5)), so:We get rid of parentheses
2(a+5)
We multiply parentheses
2a+10
Back to the equation:
-(2a+10)
3a-2a-10-12=0
We add all the numbers together, and all the variables
a-22=0
We move all terms containing a to the left, all other terms to the right
a=22
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