3(a-4)=5(a+1)

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Solution for 3(a-4)=5(a+1) equation: 



3(a-4)=5(a+1)

We move all terms to the left:

3(a-4)-(5(a+1))=0

We multiply parentheses

3a-(5(a+1))-12=0



We calculate terms in parentheses: -(5(a+1)), so:

5(a+1)

We multiply parentheses

5a+5

Back to the equation:

-(5a+5)



We get rid of parentheses

3a-5a-5-12=0

We add all the numbers together, and all the variables

-2a-17=0

We move all terms containing a to the left, all other terms to the right

-2a=17

a=17/-2

a=-8+1/2

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