3(a-4)=6a-(3a+12)

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Solution for 3(a-4)=6a-(3a+12) equation: 


Simplifying
3(a + -4) = 6a + -1(3a + 12)

Reorder the terms:
3(-4 + a) = 6a + -1(3a + 12)
(-4 * 3 + a * 3) = 6a + -1(3a + 12)
(-12 + 3a) = 6a + -1(3a + 12)

Reorder the terms:
-12 + 3a = 6a + -1(12 + 3a)
-12 + 3a = 6a + (12 * -1 + 3a * -1)
-12 + 3a = 6a + (-12 + -3a)

Reorder the terms:
-12 + 3a = -12 + 6a + -3a

Combine like terms: 6a + -3a = 3a
-12 + 3a = -12 + 3a

Add '12' to each side of the equation.
-12 + 12 + 3a = -12 + 12 + 3a

Combine like terms: -12 + 12 = 0
0 + 3a = -12 + 12 + 3a
3a = -12 + 12 + 3a

Combine like terms: -12 + 12 = 0
3a = 0 + 3a
3a = 3a

Add '-3a' to each side of the equation.
3a + -3a = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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