3(a-4)=6a-(4a+12)

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Solution for 3(a-4)=6a-(4a+12) equation: 



3(a-4)=6a-(4a+12)

We move all terms to the left:

3(a-4)-(6a-(4a+12))=0

We multiply parentheses

3a-(6a-(4a+12))-12=0



We calculate terms in parentheses: -(6a-(4a+12)), so:

6a-(4a+12)

We get rid of parentheses

6a-4a-12

We add all the numbers together, and all the variables

2a-12

Back to the equation:

-(2a-12)



We get rid of parentheses

3a-2a+12-12=0

We add all the numbers together, and all the variables

a=0

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