3(a-5)+3=4(a-3)-a

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Solution for 3(a-5)+3=4(a-3)-a equation: 


Simplifying
3(a + -5) + 3 = 4(a + -3) + -1a

Reorder the terms:
3(-5 + a) + 3 = 4(a + -3) + -1a
(-5 * 3 + a * 3) + 3 = 4(a + -3) + -1a
(-15 + 3a) + 3 = 4(a + -3) + -1a

Reorder the terms:
-15 + 3 + 3a = 4(a + -3) + -1a

Combine like terms: -15 + 3 = -12
-12 + 3a = 4(a + -3) + -1a

Reorder the terms:
-12 + 3a = 4(-3 + a) + -1a
-12 + 3a = (-3 * 4 + a * 4) + -1a
-12 + 3a = (-12 + 4a) + -1a

Combine like terms: 4a + -1a = 3a
-12 + 3a = -12 + 3a

Add '12' to each side of the equation.
-12 + 12 + 3a = -12 + 12 + 3a

Combine like terms: -12 + 12 = 0
0 + 3a = -12 + 12 + 3a
3a = -12 + 12 + 3a

Combine like terms: -12 + 12 = 0
3a = 0 + 3a
3a = 3a

Add '-3a' to each side of the equation.
3a + -3a = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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