3(a-5)+4a=3(3a+4)

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Solution for 3(a-5)+4a=3(3a+4) equation: 



3(a-5)+4a=3(3a+4)

We move all terms to the left:

3(a-5)+4a-(3(3a+4))=0

We add all the numbers together, and all the variables

4a+3(a-5)-(3(3a+4))=0

We multiply parentheses

4a+3a-(3(3a+4))-15=0



We calculate terms in parentheses: -(3(3a+4)), so:

3(3a+4)

We multiply parentheses

9a+12

Back to the equation:

-(9a+12)



We add all the numbers together, and all the variables

7a-(9a+12)-15=0

We get rid of parentheses

7a-9a-12-15=0

We add all the numbers together, and all the variables

-2a-27=0

We move all terms containing a to the left, all other terms to the right

-2a=27

a=27/-2

a=-13+1/2

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