3(a-5)=19=-2

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Solution for 3(a-5)=19=-2 equation: 



3(a-5)=19=-2

We move all terms to the left:

3(a-5)-(19)=0

We multiply parentheses

3a-15-19=0

We add all the numbers together, and all the variables

3a-34=0

We move all terms containing a to the left, all other terms to the right

3a=34

a=34/3

a=11+1/3

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