3(a-5)=2(4a-1)

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Solution for 3(a-5)=2(4a-1) equation: 



3(a-5)=2(4a-1)

We move all terms to the left:

3(a-5)-(2(4a-1))=0

We multiply parentheses

3a-(2(4a-1))-15=0



We calculate terms in parentheses: -(2(4a-1)), so:

2(4a-1)

We multiply parentheses

8a-2

Back to the equation:

-(8a-2)



We get rid of parentheses

3a-8a+2-15=0

We add all the numbers together, and all the variables

-5a-13=0

We move all terms containing a to the left, all other terms to the right

-5a=13

a=13/-5

a=-2+3/5

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