3(abs(3x-4))+8=21

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Solution for 3(abs(3x-4))+8=21 equation:


Simplifying
3(abs(3x + -4)) + 8 = 21

Reorder the terms:
3(abs(-4 + 3x)) + 8 = 21
3((-4 * abs + 3x * abs)) + 8 = 21
3((-4abs + 3absx)) + 8 = 21
(-4abs * 3 + 3absx * 3) + 8 = 21
(-12abs + 9absx) + 8 = 21

Reorder the terms:
8 + -12abs + 9absx = 21

Solving
8 + -12abs + 9absx = 21

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -12abs + -8 + 9absx = 21 + -8

Reorder the terms:
8 + -8 + -12abs + 9absx = 21 + -8

Combine like terms: 8 + -8 = 0
0 + -12abs + 9absx = 21 + -8
-12abs + 9absx = 21 + -8

Combine like terms: 21 + -8 = 13
-12abs + 9absx = 13

Reorder the terms:
-13 + -12abs + 9absx = 13 + -13

Combine like terms: 13 + -13 = 0
-13 + -12abs + 9absx = 0

The solution to this equation could not be determined.

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