3(b+1)+b=3(b-3)-1

Solution for 3(b+1)+b=3(b-3)-1 equation:

Simplifying
3(b + 1) + b = 3(b + -3) + -1

Reorder the terms:
3(1 + b) + b = 3(b + -3) + -1
(1 * 3 + b * 3) + b = 3(b + -3) + -1
(3 + 3b) + b = 3(b + -3) + -1

Combine like terms: 3b + b = 4b
3 + 4b = 3(b + -3) + -1

Reorder the terms:
3 + 4b = 3(-3 + b) + -1
3 + 4b = (-3 * 3 + b * 3) + -1
3 + 4b = (-9 + 3b) + -1

Reorder the terms:
3 + 4b = -9 + -1 + 3b

Combine like terms: -9 + -1 = -10
3 + 4b = -10 + 3b

Solving
3 + 4b = -10 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
3 + 4b + -3b = -10 + 3b + -3b

Combine like terms: 4b + -3b = 1b
3 + 1b = -10 + 3b + -3b

Combine like terms: 3b + -3b = 0
3 + 1b = -10 + 0
3 + 1b = -10

Add '-3' to each side of the equation.
3 + -3 + 1b = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1b = -10 + -3
1b = -10 + -3

Combine like terms: -10 + -3 = -13
1b = -13

Divide each side by '1'.
b = -13

Simplifying
b = -13