3(b+1)4(b-5)=

Solution for 3(b+1)4(b-5)= equation:

Simplifying
3(b + 1) * 4(b + -5) = 0

Reorder the terms:
3(1 + b) * 4(b + -5) = 0

Reorder the terms:
3(1 + b) * 4(-5 + b) = 0

Reorder the terms for easier multiplication:
3 * 4(1 + b)(-5 + b) = 0

Multiply 3 * 4
12(1 + b)(-5 + b) = 0

Multiply (1 + b) * (-5 + b)
12(1(-5 + b) + b(-5 + b)) = 0
12((-5 * 1 + b * 1) + b(-5 + b)) = 0
12((-5 + 1b) + b(-5 + b)) = 0
12(-5 + 1b + (-5 * b + b * b)) = 0
12(-5 + 1b + (-5b + b2)) = 0

Combine like terms: 1b + -5b = -4b
12(-5 + -4b + b2) = 0
(-5 * 12 + -4b * 12 + b2 * 12) = 0
(-60 + -48b + 12b2) = 0

Solving
-60 + -48b + 12b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '12'.
12(-5 + -4b + b2) = 0

Factor a trinomial.
12((-1 + -1b)(5 + -1b)) = 0

Ignore the factor 12.
Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {-1, 5}