3(b+1)=(b-5)

Solution for 3(b+1)=(b-5) equation:

Simplifying
3(b + 1) = (b + -5)

Reorder the terms:
3(1 + b) = (b + -5)
(1 * 3 + b * 3) = (b + -5)
(3 + 3b) = (b + -5)

Reorder the terms:
3 + 3b = (-5 + b)

Remove parenthesis around (-5 + b)
3 + 3b = -5 + b

Solving
3 + 3b = -5 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
3 + 3b + -1b = -5 + b + -1b

Combine like terms: 3b + -1b = 2b
3 + 2b = -5 + b + -1b

Combine like terms: b + -1b = 0
3 + 2b = -5 + 0
3 + 2b = -5

Add '-3' to each side of the equation.
3 + -3 + 2b = -5 + -3

Combine like terms: 3 + -3 = 0
0 + 2b = -5 + -3
2b = -5 + -3

Combine like terms: -5 + -3 = -8
2b = -8

Divide each side by '2'.
b = -4

Simplifying
b = -4