3(b+1)=1+2s

Solution for 3(b+1)=1+2s equation:

Simplifying
3(b + 1) = 1 + 2s

Reorder the terms:
3(1 + b) = 1 + 2s
(1 * 3 + b * 3) = 1 + 2s
(3 + 3b) = 1 + 2s

Solving
3 + 3b = 1 + 2s

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3b = 1 + -3 + 2s

Combine like terms: 3 + -3 = 0
0 + 3b = 1 + -3 + 2s
3b = 1 + -3 + 2s

Combine like terms: 1 + -3 = -2
3b = -2 + 2s

Divide each side by '3'.
b = -0.6666666667 + 0.6666666667s

Simplifying
b = -0.6666666667 + 0.6666666667s