3(b+1)=2(b+6)

Solution for 3(b+1)=2(b+6) equation:

Simplifying
3(b + 1) = 2(b + 6)

Reorder the terms:
3(1 + b) = 2(b + 6)
(1 * 3 + b * 3) = 2(b + 6)
(3 + 3b) = 2(b + 6)

Reorder the terms:
3 + 3b = 2(6 + b)
3 + 3b = (6 * 2 + b * 2)
3 + 3b = (12 + 2b)

Solving
3 + 3b = 12 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
3 + 3b + -2b = 12 + 2b + -2b

Combine like terms: 3b + -2b = 1b
3 + 1b = 12 + 2b + -2b

Combine like terms: 2b + -2b = 0
3 + 1b = 12 + 0
3 + 1b = 12

Add '-3' to each side of the equation.
3 + -3 + 1b = 12 + -3

Combine like terms: 3 + -3 = 0
0 + 1b = 12 + -3
1b = 12 + -3

Combine like terms: 12 + -3 = 9
1b = 9

Divide each side by '1'.
b = 9

Simplifying
b = 9