3(b+1)=2(b-5)

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Solution for 3(b+1)=2(b-5) equation: 



3(b+1)=2(b-5)

We move all terms to the left:

3(b+1)-(2(b-5))=0

We multiply parentheses

3b-(2(b-5))+3=0



We calculate terms in parentheses: -(2(b-5)), so:

2(b-5)

We multiply parentheses

2b-10

Back to the equation:

-(2b-10)



We get rid of parentheses

3b-2b+10+3=0

We add all the numbers together, and all the variables

b+13=0

We move all terms containing b to the left, all other terms to the right

b=-13

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