3(b+1)=36+3

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Solution for 3(b+1)=36+3 equation: 



3(b+1)=36+3

We move all terms to the left:

3(b+1)-(36+3)=0

We add all the numbers together, and all the variables

3(b+1)-39=0

We multiply parentheses

3b+3-39=0

We add all the numbers together, and all the variables

3b-36=0

We move all terms containing b to the left, all other terms to the right

3b=36

b=36/3

b=12

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