3(b+1)=4(b-3)+7

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Solution for 3(b+1)=4(b-3)+7 equation: 



3(b+1)=4(b-3)+7

We move all terms to the left:

3(b+1)-(4(b-3)+7)=0

We multiply parentheses

3b-(4(b-3)+7)+3=0



We calculate terms in parentheses: -(4(b-3)+7), so:

4(b-3)+7

We multiply parentheses

4b-12+7

We add all the numbers together, and all the variables

4b-5

Back to the equation:

-(4b-5)



We get rid of parentheses

3b-4b+5+3=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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